NEETChemistryAldehydes and Ketones
An aromatic compound ‘A’ (Molecular formula C 8 H 8 O) gives positive 2, 4-DNP test. It gives a yellow precipitate of compound ‘B’ on treatment with iodine and sodium hydroxide solution. Compound ‘A’ does not give Tollens or Fehling’s test. On drastic oxidation with potassium permanganate it forms a carboxylic acid ‘C’ (Molecular formula C 7 H 6 O 2 ), which is also formed along with the yellow compound in the above
Options
- AA=Acetophenone, B=CHCl 3 and C=Benzoic acid
- BA=Acetophenone, B=CHI 3 and C=Benzoic acid
- CA=Acetaldehyde, B=CHI 3 and C=Benzoic acid
- DA=Acetophenone, B=CHI 3 and C=Benzaldehyde
Correct answer
B. A=Acetophenone, B=CHI 3 and C=Benzoic acid
Step-by-step solution
Correct Option is : (B) A=Acetophenone, B=CHI 3 and C=Benzoic acid