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NEETChemistryAldehydes and Ketones

An aromatic compound ‘A’ (Molecular formula C 8 H 8 O) gives positive 2, 4-DNP test. It gives a yellow precipitate of compound ‘B’ on treatment with iodine and sodium hydroxide solution. Compound ‘A’ does not give Tollens or Fehling’s test. On drastic oxidation with potassium permanganate it forms a carboxylic acid ‘C’ (Molecular formula C 7 H 6 O 2 ), which is also formed along with the yellow compound in the above

Options

  1. AA=Acetophenone, B=CHCl 3 and C=Benzoic acid
  2. BA=Acetophenone, B=CHI 3 and C=Benzoic acid
  3. CA=Acetaldehyde, B=CHI 3 and C=Benzoic acid
  4. DA=Acetophenone, B=CHI 3 and C=Benzaldehyde

Correct answer

B. A=Acetophenone, B=CHI 3 and C=Benzoic acid

Step-by-step solution

Correct Option is : (B) A=Acetophenone, B=CHI 3 and C=Benzoic acid

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