Equal volumes of three acid solutions of pH 3,4 and 5 are mixed in a vessel. What will be the H ⁺ ion concentration in the mixture?

Step-by-step solution

Let the volume of each acid (=V ) (p H ) of first, second and third acids (=3,4 ) and 5 respectively ( [H⁺ ] )of first acid ( (M₁ )=1 10⁻³ [ H⁺=1 10^ -p H ] ) ( [H⁺ ] )of second acid ( (M₂ )=1 10⁻⁴ ) ( [H⁺ ] )of third acid ( (M₃ )=1 10⁻⁵ ) Total ( [H⁺ ] )concentrated of mixture ( aligned & (M)= M₁ V₁+M₂ V₂+M₃ V₃ V₁+V₂+V₃ & = 1 10^3 V+1 10^4 V+1 10^5 V V+V+V & = 1 10^3 V(1+0.1+0.01) 3 V & = 1.11 10^3 3 =3.7 10⁻⁴ M aligned )