NEET2010ChemistryAldehydes and KetonesActual
Compound A (molecular formula C ₃ H ₈ O ) is treated with acidified potassium dichromate to form a product B (molecular formula C ₃ H ₆ O ). B forms a shining silver mirror on warming with ammoniacal silver nitrate. B when treated with an aqueous solution of H ₂ NCONHNH ₂ . HCl and sodium acetate gives a product C . Identify the structure of C .
Options
- ACH ₃ CH ₂ CH = NNHCONH ₂
- BCH ₃ CH ₂ CH = NCONHNH ₂
Correct answer
A. CH ₃ CH ₂ CH = NNHCONH ₂
Step-by-step solution
Reaction of B indicates that B is an aldehyde thus B should be C ₂ H ₅ CHO or CH ₃ CH ₂ CHO and therefore C should be CH ₃ CH ₂ CH = NNHCONH ₂ .