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NEET2012ChemistryAldehydes and KetonesActual

CH ₃ CHO + HCHO [ Heat ] Dil. NaOH A [ H ₃ O ⁺] HCN B The structure of compound B is

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Step-by-step solution

It undergoes aldol condensation to give ( CH ₂( OH ) CH ₂( CHO ) ) which dehydrates to give ( CH ₂ CHCHO ) When this is treated with ( HCN / H ₃ O ⁺ ), it gives the carboxylic acid. ( aligned & CH ₃ CHO + HCHO Dil. NaOH CH ₂( OH ) CH ₂ CHO & CH ₂( OH ) CH ₂ CHO CH ₂= CHCHO & CH ₂= CHCHO HCN CH ₂= CHCH ( OH )( CN ) & CH ₂= CHCH ( OH )( CN ) H ₃ O ⁺ CH ₂= CH - CH ( COOH )( OH ) aligned )

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