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AIIMS 2016
Exam
AIIMS
Year
2016
Subject
Physics
Chapter
Motion in One Dimension

AIIMS 2016 · Physics · Motion in One Dimension

A ball is dropped from the top of a building 100 ~m high. At the...

A ball is dropped from the top of a building 100 m100 \mathrm{~m} high. At the same instant another ball is thrown upwards with a velocity of 40 m/s40 \mathrm{~m} / \mathrm{s} from the bottom of the building. The two balls will meet after

Options

  1. A3 s3 \mathrm{~s}
  2. B2 s2 \mathrm{~s}
  3. C2.5 s2.5 \mathrm{~s}
  4. D5 s5 \mathrm{~s}

Correct answer

C. 2.5 s2.5 \mathrm{~s}

Step-by-step solution

Let balls meet after t st \mathrm{~s}. The distance travelled by the ball coming down is s1=12gt2s_1=\frac{1}{2} g t^2 Distance travelled by the other ball s2=40t−12gt2∵s1+s2=100 m∴12gt2+40t−12gt2=100 mt=10040=2.5 s\begin{array}{ll} & s_2=40 t-\frac{1}{2} g t^2 \\ \because \quad & s_1+s_2=100 \mathrm{~m} \\ \therefore \quad & \frac{1}{2} g t^2+40 t-\frac{1}{2} g t^2=100 \mathrm{~m} \\ & t=\frac{100}{40}=2.5 \mathrm{~s}\end{array}
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