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BITSAT 2021
Exam
BITSAT
Year
2021
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

BITSAT 2021 · Chemistry · Chemical Bonding and Molecular Structure

Which of the following represents the correct order of Cl- O bond...

Which of the following represents the correct order of Cl−\mathrm{Cl}-O\mathrm{O}bondlengthsinbond lengths inClO−\mathrm{ClO}^{-}, ClO2−\mathrm{ClO}_{2}^{-}, ClO3−\mathrm{ClO}_{3}^{-}, ClO4−\mathrm{ClO}_{4}^{-}? \text{? }

Options

  1. AClO4−=ClO3−=ClO2−=ClO−\mathrm{ClO}_{4}^{-}=\mathrm{ClO}_{3}^{-}=\mathrm{ClO}_{2}^{-}=\mathrm{ClO}^{-}
  2. BClO−<ClO2−<ClO3−<ClO4−\mathrm{ClO}^{-} < \mathrm{ClO}_{2}^{-} < \mathrm{ClO}_{3}^{-} < \mathrm{ClO}_{4}^{-}
  3. CClO4−<ClO3−<ClO2−<ClO−\mathrm{ClO}_{4}^{-} < \mathrm{ClO}_{3}^{-} < \mathrm{ClO}_{2}^{-} < \mathrm{ClO}^{-}
  4. DClO3−<ClO4−<ClO2−<ClO−\mathrm{ClO}_{3}^{-} < \mathrm{ClO}_{4}^{-} < \mathrm{ClO}_{2}^{-} < \mathrm{ClO}^{-}

Correct answer

C. ClO4−<ClO3−<ClO2−<ClO−\mathrm{ClO}_{4}^{-} < \mathrm{ClO}_{3}^{-} < \mathrm{ClO}_{2}^{-} < \mathrm{ClO}^{-}

Step-by-step solution

The b.o in Cl−O−\mathrm{Cl}-\mathrm{O}^{-} is 1 The b.o in O=Cl−O−\mathrm{O}=\mathrm{Cl}-\mathrm{O}^{-} is 1.51.5 The b.o. in O=Cl=O\mathrm{O}=\mathrm{Cl}=\mathrm{O} is 53=1.66\frac{5}{3}=1.66 The b.o. in O=∥OOl−O−\mathrm{O}=\underset{\mathrm{O}}{\stackrel{\mathrm{O}}{\|}} \mathrm{l}-\mathrm{O}^{-} is 74=1.75\frac{7}{4}=1.75 The bond length increases as b.o. decreases.
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