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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

BITSAT 2013 · Chemistry · Chemical Bonding and Molecular Structure

Using MOT, which of the following pairs denote paramagnetic species?

Using MOT, which of the following pairs denote paramagnetic species?

Options

  1. AB2\mathrm{B}_{2} and C2\mathrm{C}_{2}
  2. BB2\mathrm{B}_{2} and O2\mathrm{O}_{2}
  3. CN2\mathrm{N}_{2} and C2\mathrm{C}_{2}
  4. DO2\mathrm{O}_{2} and O22−\mathrm{O}_{2}^{2-}

Correct answer

B. B2\mathrm{B}_{2} and O2\mathrm{O}_{2}

Step-by-step solution

\mathrm{B}_{2}andand\mathrm{O}_{2}areparamagneticduetopresenceofunpairedelectron.MOelectronicconfigurationofare paramagnetic due to presence of unpaired electron. MO electronic configuration of\mathrm{B}_{2}is:is:\sigma1 s^{2} σ∗\sigma^{*}1 s^{2} σ\sigma2 s^{2} σ∗\sigma^{*}2 s^{2} \pi2 p_x^{1}=\pi2 p_y^{1} MO electorn i.e. configuration of \mathrm{O}_{2}is:is:σ1s2σ∗1s2σ2s2σ∗2s2σ2pz2π2px2=π2py2π∗2px1=π∗2py1\begin{array}{l}\sigma1 s^{2} \sigma^{*}1 s^{2} \sigma2 s^{2} \sigma^{*}2 s^{2} \sigma2 p_z^{2} \pi2 p_x^{2} \\ =\pi2 p_y^{2} \pi* 2 p_x^{1}=\pi* 2 p_y^{1} \end{array}$
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