The correct bond order in the following species is:

Step-by-step solution

O ₂⁺ ion - Total number of electrons (16-1)=15 E.C.: array r 1 s² ^ * 1 s² 2 s² ^ * 2 s² 2 p_ z ² 2 p_ x ²= 2 p_ y ² ^ * 2 p_ x ¹= ^ * 2 p_ y Bond order = N _ b - N _ a 2 = 10-5 2 = 5 2 =2 1 2 array O ₂⁻ (Super oxide ion): Total number of electrons (16+1)=17 E.C.: array l 1s ² ^ * 1 s² 2 s² ^ * 2 s² 2 p_ z ² 2 p_ x ²= 2 p_ y ² ^ * 2 p_ x ²= ^ * 2 p_ y ¹ Bond order = ( N _ b - N _ a ) 2 = 10-7 2 = 3 2 =1 1 2 array O ₂²⁺ ion: Total number of electrons =(16-2)=14 E.C. array l 1 s² ^ * 1 s² 2 s² ^ * 2 s² 2 p_ x ²= 2 p_