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BITSAT 2011
Exam
BITSAT
Year
2011
Subject
Chemistry
Chapter
Chemical Bonding and Molecular Structure

BITSAT 2011 · Chemistry · Chemical Bonding and Molecular Structure

The correct bond order in the following species is:

The correct bond order in the following species is:

Options

  1. AO22+<O2−<O2+\mathrm{O}_{2}^{2+}< \mathrm{O}_{2}^{-}< \mathrm{O}_{2}^{+}
  2. BO2+<O2−<O22+\mathrm{O}_{2}^{+}< \mathrm{O}_{2}^{-}< \mathrm{O}_{2}^{2+}
  3. CO2−<O2+<O22+\mathrm{O}_{2}^{-}< \mathrm{O}_{2}^{+}< \mathrm{O}_{2}^{2+}
  4. DO22+<O2+<O2−\mathrm{O}_{2}^{2+}< \mathrm{O}_{2}^{+}< \mathrm{O}_{2}^{-}

Correct answer

C. O2−<O2+<O22+\mathrm{O}_{2}^{-}< \mathrm{O}_{2}^{+}< \mathrm{O}_{2}^{2+}

Step-by-step solution

O2+\mathrm{O}_{2}^{+} ion - Total number of electrons (16−1)=15(16-1)=15 E.C.: σ1s2σ∗1s2σ2s2σ∗2s2σ2pz2π2px2=π2py2π∗2px1=π∗2py Bond order =Nb−Na2=10−52=52=212\begin{array}{r} \sigma1 s^{2} \sigma^{*}1 s^{2} \sigma2 s^{2} \sigma^{*}2 s^{2} \sigma2 p_z^{2} \\ \pi2 p_x^{2}=\pi2 p_y^{2} \pi^{*}2 p_x^{1}=\pi^{*}2 p_{y} \\ \text{ Bond order }=\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}=\frac{10-5}{2}=\frac{5}{2}=2 \frac{1}{2} \end{array}\mathrm{O}_{2}^{-}(Superoxideion):Totalnumberofelectrons(Super oxide ion): Total number of electrons(16+1)=17E.C.:E.C.: \sigma1s 2σ∗1s2σ2s2σ∗2s2σ2pz2π2px2=π2py2π∗2px2=π∗2py1 Bond order =(Nb−Na)2=10−72=32=112\begin{array}{l}\text{ \sigma1s }^{2} \sigma^{*}1 s^{2} \sigma2 s^{2} \sigma^{*}2 s^{2} \sigma2 p_z^{2} \\ \pi2 p_x^{2}=\pi2 p_y^{2} \pi^{*}2 p_x^{2}=\pi^{*}2 p_y^{1} \\ \text{ Bond order }=\frac{\left(\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}\right)}{2}=\frac{10-7}{2}=\frac{3}{2}=1 \frac{1}{2} \end{array}O22+\mathrm{O}_{2}^{2+} ion: Total number of electrons =(16−2)=14=(16-2)=14 E.C. σ1s2σ∗1s2σ2s2σ∗2s2π2px2=π2py2σ2pz2 Bond order =(Nb−Na)2=10−42=62=3\begin{array}{l} \sigma1 s^{2} \sigma^{*}1 s^{2} \sigma2 s^{2} \sigma^{*}2 s^{2} \pi2 p_x^{2}=\pi2 p_y^{2} \sigma2 p_z^{2} \\ \text{ Bond order }=\frac{\left(N_{b}-N_{a}\right)}{2}=\frac{10-4}{2}=\frac{6}{2}=3 \end{array}So bond order: \mathrm{O}_{2}^{-}< \mathrm{O}_{2}^{+}< \mathrm{O}_{2}^{2+}$
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