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BITSAT2017ChemistryChemical KineticsActual

A graph is plotted between log K versus 1 T for calculation of activation energy E a . The correct plot is

Correct answer

1

Step-by-step solution

According to Arrhenius equation, k ∝ T and k = Ae − Ea ​ / RT logk = logA - E a 2 . 303 × R ​ ​ × 1 T ​ y = mx + c , the equation of straight line The value of log k should increase uniformily with T or decrease with 1 T . From this, that the slope is negative, which means that angle with x - axis is greater than 90° also that the point on which the straight line of graph intercepts the y - axis is log A which is positive. Hence all the conclusions point out towards

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