A graph is plotted between log K versus (1)/(T) for calculation of...

According to Arrhenius equation,

$k ∝ T$ and $k = {Ae}^{- Ea / RT}$

$logk = logA - \dfrac{Ea}{2. 303 \times R} \times \dfrac{1}{T}$

$y = mx + c$, the equation of straight line

The value of log $k$ should increase uniformily with $T$ or decrease with $\dfrac{1}{T}$.

& & & & & & & &

From this, that the slope is negative, which means that angle with x - axis is greater than 90° also that the point on which the straight line of graph intercepts the y - axis is log A which is positive.

Hence all the conclusions point out towards option b as it has negative slope and a positive y intercept.