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BITSAT 2018
Exam
BITSAT
Year
2018
Subject
Chemistry
Chapter
Coordination Compounds

BITSAT 2018 · Chemistry · Coordination Compounds

Which of the following is the correct order for the wavelength if...

Which of the following is the correct order for the wavelength if absorption in the visible region.

Options

  1. A[Ni(NO2)6]4−<[Ni(NH3)6]2+<[Ni(H2O)6]2+\left[Ni\left({NO}_{2}\right)6\right]4 - < \left[Ni\left({NH}_{3}\right)6\right]2 + < \left[Ni\left({H}_{2}O\right)6\right]2 +
  2. B[Ni(NO2)6]4−<[Ni(H2O)6]2+<[Ni(NH3)6]2+\left[Ni\left({NO}_{2}\right)6\right]4 - < \left[Ni\left({H}_{2}O\right)6\right]2 + < \left[Ni\left({NH}_{3}\right)6\right]2 +
  3. C[Ni(H2O)6]2+<[Ni(NH3)6]2+<[Ni(NO2)6]4−\left[Ni\left({H}_{2}O\right)6\right]2 + < \left[Ni\left({NH}_{3}\right)6\right]2 + < \left[Ni\left({NO}_{2}\right)6\right]4 -
  4. D[Ni(NH3)6]2+<[Ni(H2O)6]2+<[Ni(NO2)6]4−\left[Ni\left({NH}_{3}\right)6\right]2 + < \left[Ni\left({H}_{2}O\right)6\right]2 + < \left[Ni\left({NO}_{2}\right)6\right]4 -

Correct answer

A. [Ni(NO2)6]4−<[Ni(NH3)6]2+<[Ni(H2O)6]2+\left[Ni\left({NO}_{2}\right)6\right]4 - < \left[Ni\left({NH}_{3}\right)6\right]2 + < \left[Ni\left({H}_{2}O\right)6\right]2 +

Step-by-step solution

When central metal ion is same (here Ni2+{Ni}^{2 +} ), the absorption of colour depends on the ligand.

According to spectrochemical series, various ligands are as follows

I<Br−<Cl−<NO3−<F−<H2OI < {Br}^{-} < {Cl}^{-} < {NO}_{3}^{-} < F^{-} < {H}_{2}O

<NH3<NO2−<CN−<CO< {NH}_{3} < {NO}_{2}^{-} < {CN}^{-} < CO

Thus, H2O{H}_{2}O~is the weakest ligand among these, therefore the absorbed energy will be lowest in
[Ni(H2O)6]2+,\left[Ni\left({H}_{2}O\right)6\right]2 +, so it will absorb highest wavelength (red light).

E∝1λE ∝ \dfrac{1}{λ}

∴∴~The order of increasing wavelength is

\left[Ni\left({NO}_{2}\right)6\right]4 - < \left[Ni\left({NH}_{3}\right)6\right]2 + < \left[Ni\left({H}_{2}O\right)6\right]2 +$

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