What time in sec is required for depositing all the silver present in 125 ml of 1 M AgNO 3 solution by passing a current of 241 . 25 A (Given 1 F = 96500 C )

Step-by-step solution

Given, 125   ml of 1   M   AgNO 3 which is equal to 13 . 5   g of Ag ∵   1000   ml of AgNO 3 = 108   g of Ag ∴   125   ml of AgNO 3 = 108 × 125 1000 = 13 . 5   g Also, ∵   108   g of Ag is deposited by = 96500   C ∴   13 . 5   g of Ag is deposited by = 96500 × 13 . 5 108 = 12062 . 5   C ∵   Q = it ∴   t (time) = Q / i = 12062 . 50 241 . 25 ,   t = 50   sec