What time in sec is required for depositing all the silver present...

Given, $125ml$ of $1M{AgNO}_{3}$

which is equal to $13. 5g$ of $Ag$

$∵ 1000ml$ of ${AgNO}_{3} = 108g$ of $Ag$

$∴ 125ml$ of ${AgNO}_{3} = \dfrac{108 \times 125}{1000} = 13. 5g$

Also, $∵ 108g$ of $Ag$ is deposited by $= 96500C$

$∴ 13. 5g$ of $Ag$ is deposited by $= \dfrac{96500 \times 13. 5}{108} = 12062. 5C$

$∵ Q = it$

$∴ t$ (time) $= Q / i = \dfrac{12062. 50}{241. 25}, t = 50sec$