0 . 5 F of electricity is passed through 500 mL of copper sulphate solution. The amount of copper which can be deposited will be

Step-by-step solution

Cu 2 + + 2 e - ⟶ Cu   . . . i According to Faraday's first law, when an electric current is passed through an electrolyte, amount of substance deposited is directly proportional to the quantity of electric charge passed through the electrolyte. ∵ 1   mol of 63 . 5   g of Cu is obtained by passing 2 F of electricity. Mass of Cu obtained by passing 1 F of electricity = 63 . 5 2 g ∴ Mass of Cu obtained by passing 0 . 5 F of electricity = 63 . 5 2 × 0 . 5 = 15 . 80   g