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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Chemistry
Chapter
Redox Reactions

BITSAT 2013 · Chemistry · Redox Reactions

The oxidation state of sulphur in Na_ 2 S_ 4 O_ 6 is

The oxidation state of sulphur in Na2S4O6\mathrm{Na}_{2} \mathrm{ S}_{4} \mathrm{O}_{6} is

Options

  1. A6
  2. B+32\frac{+3}{2}
  3. C+52\frac{+5}{2}
  4. D-2

Correct answer

C. +52\frac{+5}{2}

Step-by-step solution

Na2S4O62+4x−12=04x−10=0x=104=+52\mathrm{Na}_{2} \mathrm{ S}_{4} \mathrm{O}_{6}2+4 x-12=04 x-10=0x=\frac{10}{4}=\frac{+5}{2} Oxidation state of S\mathrm{S} is =+52=\frac{+5}{2}
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