Volume of 3 % solution of sodium carbonate necessary to neutralise a litre of 0.1 ~N sulphuric acid

Step-by-step solution

Normality of 3 % Na ₂ CO ₃ N = 3 1000 53 100 =0.566 ~N For H ₂ SO ₄ sol. N ₁=0.1, ~V ₁=100 ~mL For Na ₂ CO ₃ sol. N ₂=0.566 Now apply N ₁ ~V ₁= N ₂ ~V ₂ V ₂= N ₁ ~V ₁ ~N ₂ = 0.1 1000 ~mL 0.566 =176.66 ~mL