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BITSAT 2012
Exam
BITSAT
Year
2012
Subject
Chemistry
Chapter
Redox Reactions

BITSAT 2012 · Chemistry · Redox Reactions

0.45 g of acid molecular weight 90 is neutralised by 20 ml of 0.5 N...

0.45g0.45 \mathrm{ g} of acid molecular weight 90 is neutralised by 20ml20 \mathrm{ml} of 0.5N0.5 \mathrm{ N} caustic potash. The basicity of acid is

Options

  1. A1
  2. B2
  3. C3
  4. D4

Correct answer

B. 2

Step-by-step solution

Eq.ofacid=Eqofbase,Eq. of acid = Eq of base,∴0.45E⋅wt=20×0.51000=Ewt=45 Basicity =M⋅wtE⋅wt=9045=2\begin{array}{l} \therefore \frac{0.45}{\mathrm{E} \cdot \mathrm{wt}}=\frac{20 \times 0.5}{1000}=\mathrm{E} \mathrm{wt}=45 \\ \text{ Basicity }=\frac{\mathrm{M} \cdot \mathrm{wt}}{\mathrm{E} \cdot \mathrm{wt}}=\frac{90}{45}=2 \end{array}$$
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