BITSAT2011ChemistryRedox ReactionsActual
1.520 ~g of hydroxide of a metal on ignition gave 0.995 ~g of oxide. The equivalent weight of metal is:
Options
- A1.52
- B0.995
- C190
- D9
Correct answer
D. 9
Step-by-step solution
Let E be the equivalent weight of the metal So, E+17 E+8 = 1.52 0.995 [17 is equivalent weight of OH and 8 is equivalent weight of oxygen] array l 0.995 E +17 0.995= E 1.52+8 1.52 0.525 E =16.915-12.16=4.755 E = 4.755 0.525 =9 array