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BITSAT 2016
Exam
BITSAT
Year
2016
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

BITSAT 2016 · Chemistry · Some Basic Concepts of Chemistry

A compound of Xe and F is found to have 53.5 \% of Xe. What is...

A compound of Xe and F\mathrm{F} is found to have 53.5%53.5 \% of Xe. What is oxidation number of Xe in this compound?

Options

  1. A-4
  2. B0
  3. C4
  4. D6

Correct answer

D. 6

Step-by-step solution

Xe=53.5%∴F=46.5%\mathrm{Xe}=53.5 \% \therefore \mathrm{F}=46.5 \% Relative number of atoms Xe =53.5131.2=0.4 and F=46.519=2.4SimpleratioXe=1\frac{53.5}{131.2}=0.4 \text{ and } \mathrm{F}=\frac{46.5}{19}=2.4 Simple ratio \mathrm{Xe}=1 and F=6;\mathrm{F}=6 ; Molecular formula is XeF6\mathrm{XeF}_{6} O. N\mathrm{N}.of Xe\mathrm{Xe} is +6
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