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BITSAT 2016
Exam
BITSAT
Year
2016
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

BITSAT 2016 · Chemistry · Some Basic Concepts of Chemistry

Formation of polyethylene from calcium carbide takes place as...

Formation of polyethylene from calcium carbide takes place as follows CaC2+2H2O⟶Ca(OH)2+C2H2C2H2+H2⟶C2H4nC2H4⟶(−CH2−CH2−)n\begin{array}{l}\mathrm{CaC}_{2}+2 \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{C}_{2} \mathrm{H}_{2}\\ \mathrm{C}_{2} \mathrm{H}_{2}+\mathrm{H}_{2} \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}\\ \mathrm{nC}_{2} \mathrm{H}_{4} \longrightarrow\left(-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\right)_{\mathrm{n}} \end{array} The amount of polyethylene obtained from 64.1kg64.1 \mathrm{ kg} of CaC2\mathrm{CaC}_{2} is

Options

  1. A7kg7 \mathrm{ kg}
  2. B14kg14 \mathrm{ kg}
  3. C21kg21 \mathrm{ kg}
  4. D28kg28 \mathrm{ kg}

Correct answer

D. 28kg28 \mathrm{ kg}

Step-by-step solution

The concerned chemical reactions are (i) CaC2+2H2O→Ca(OH)264kg+C2H2 Ethyne, 26kg\underset{64 \mathrm{ kg}}{\mathrm{CaC}_{2}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{Ca}(\mathrm{OH})_{2}}+\underset{\text{ Ethyne, } 26 \mathrm{ kg}}{\mathrm{C}_{2} \mathrm{H}_{2}} (ii) C2H2+H2→C2H4 Ethylene ,28kg (iii) nC2H2→[−CH2−CH2−]n\mathrm{C}_{2} \mathrm{H}_{2}+\mathrm{H}_{2} \rightarrow \underset{\text{ Ethylene }, 28 \mathrm{ kg}}{\mathrm{C}_{2} \mathrm{H}_{4}}\text{ (iii) } \mathrm{nC}_{2} \mathrm{H}_{2} \rightarrow\left[-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\right]_{\mathrm{n}}n×28kgn×28kg polythene  or  28kg or  28kg\begin{array}{ll}\mathrm{n} \times 28 \mathrm{ kg} & \mathrm{n} \times 28 \mathrm{ kg} \text{ polythene } \\ \text{\text{ or } } 28 \mathrm{ kg} & \text{\text{ or } } 28 \mathrm{ kg}\end{array}ThusThus64 kg\mathrm{ kg} of CaC2gives\mathrm{CaC}_{2} gives26 kg\mathrm{ kg} of acetylene which in turn gives 28kgofethylenewhose28 \mathrm{ kg} of ethylene whose28 kg\mathrm{ kg} gives 28kgofthepolymer,polythene.28 \mathrm{ kg} of the polymer, polythene.
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