How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 MHNO_ 3 ? The concentrated acid is 70 \% HNO_ 3

Correct answer: D. 45.0 g conc. HNO_ 3 Molarity (M)= wt × 1000 mol. wt. × vol(mL) 2= wt. 63 × (1000)/(250)wt=(63)/(2) g wt. of 70 \% acid =(100)/(70) × 31.5=45 g

BITSAT 2013

Exam: BITSAT
Year: 2013
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

BITSAT 2013 · Chemistry · Some Basic Concepts of Chemistry

How many grams of concentrated nitric acid solution should be used...

How many grams of concentrated nitric acid solution should be used to prepare

250 \mathrm{ mL}

2.0 \mathrm{MHNO}_{3} ?

The concentrated acid is

70 \% \mathrm{HNO}_{3}

Options

A $90.0 \mathrm{ g}$ conc. $\mathrm{HNO}_{3}$
B $70.0 \mathrm{ g}$ conc. $\mathrm{HNO}_{3}$
C $54.0 \mathrm{ g}$ conc. $\mathrm{HNO}_{3}$
D $45.0 \mathrm{ g}$ conc. $\mathrm{HNO}_{3}$

Correct answer

D. $45.0 \mathrm{ g}$ conc. $\mathrm{HNO}_{3}$

Step-by-step solution

\quad

Molarity

(\mathrm{M})=\frac{\mathrm{wt} \times 1000}{\text{ mol. wt. } \times \mathrm{vol}(\mathrm{mL})}2=\frac{\mathrm{wt}.}{63} \times \frac{1000}{250}\mathrm{wt}=\frac{63}{2} \mathrm{ g} wt. of

70 \%

acid =\frac{100}{70}

\times 31.5=45

\mathrm{ g}

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