Equal weights of NaCl and KCl are dissolved separately in equal...

Equal weights of

\mathrm{NaCl}

and

\mathrm{KCl}

are dissolved separately in equal volumes of solutions. Molarity of the two solutions will be :

Options

AEqual
BThat of $\mathrm{NaCl}$ will be less than that of $\mathrm{KCl}$
CThat of $\mathrm{NaCl}$ will be more than that of $\mathrm{KCl}$ solution
DThat of $\mathrm{NaCl}$ will be about half of that of $\mathrm{KCl}$ solution

Correct answer

C. That of $\mathrm{NaCl}$ will be more than that of $\mathrm{KCl}$ solution

Step-by-step solution

When equal weights of different solutes are present in equal volumes of solution the molarity is inversely related to molecular mass of the solute. Mol. mass of

\mathrm{NaCl}

is less than

\mathrm{KCl}

. Hence, molarity of

\mathrm{NaCl}

solution will be more.

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