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BITSAT2018ChemistryThermodynamics (C)Actual

When the heat of a reaction at constant pressure is - 25 × 10 - 3 cal and entropy change for the reaction is 7 . 4 cal deg - 1 , it is predicted that the reaction at 25 0 C is

Options

  1. Arevesible
  2. Bspontaneous
  3. Cnon-spontaneous
  4. Dirreversible

Correct answer

B. spontaneous

Step-by-step solution

Heat at constant pressure means enthalpy. i.e., ΔG = ΔH - TΔS ΔH = 2 . 5 × 10 3 cal ΔS = 7 . 4 caldeg - 1 T = 298   K ΔG = ΔH - TΔS = - 25 × 10 3 - 298 × 7 . 4 = - 4705 . 2   cal As the value of ΔG is −4705.2 cal, which is a negative value, so this reaction will be spontaneous. Hence, the process is spontaneous.

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