BITSAT2017MathematicsBinomial TheoremActual
The coefficient of x 5 in the expansion of 1 + x 21 + 1 + x 22 + … + 1 + x 30 is
Options
- AC 5 51
- BC 5 9
- CC 6 31 - C 6 21
- DC 5 30 + C 5 20
Correct answer
C. C 6 31 - C 6 21
Step-by-step solution
1 + x 21 + 1 + x 22 + … … + 1 + x 30 = 1 + x 21 1 + 1 + x 1 + … + 1 + x 9 = 1 + x 21 1 + x 10 - 1 1 + x - 1 = 1 x 1 + x 31 - 1 + x 21 ∴ Coefficient of x 5 in the given expression = Coefficient of x 5 in 1 x 1 + x 31 - 1 + x 21 = Coefficient of x 6 in 1 + x 31 - 1 + x 21 = C 6 31 - C 6 21