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BITSAT 2012
Exam
BITSAT
Year
2012
Subject
Mathematics
Chapter
Binomial Theorem

BITSAT 2012 · Mathematics · Binomial Theorem

The coefficient of x^ 20 in the expansion of (1+x^ 2 )^ 40 · (x^ 2...

The coefficient of x20x^{20} in the expansion of (1+x2)40⋅(x2+2+1x2)−5is\left(1+x^{2}\right)^{40} \cdot \left(x^{2}+2+\frac{1}{x^{2}}\right)^{-5} is

Options

  1. A30C10{ }^{30} \mathrm{C}_{10}
  2. B30C25{ }^{30} \mathrm{C}_{25}
  3. C1
  4. DNone of these

Correct answer

B. 30C25{ }^{30} \mathrm{C}_{25}

Step-by-step solution

Expression =(1+x2)40⋅(x+1x)−10=(1+x2)30⋅x10=\left(1+x^{2}\right)^{40} \cdot\left(x+\frac{1}{x}\right)^{-10}=\left(1+x^{2}\right)^{30} \cdot x^{10} The coefficient of x20inx10(1+x2)30=x^{20} in x^{10}\left(1+x^{2}\right)^{30}= the coefficient of \mathrmx10in(1+\mathrmx2)30=30C5=30C30−5=30C25\mathrmx^{10} in \left(1+\mathrmx^{2}\right)^{30}={ }^{30} \mathrm{C}_{5}={ }^{30} \mathrm{C}_{30-5}={ }^{30} \mathrm{C}_{25}
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