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BITSAT 2018
Exam
BITSAT
Year
2018
Subject
Mathematics
Chapter
Circle

BITSAT 2018 · Mathematics · Circle

Radius of the largest circle which passes through the focus of the...

Radius of the largest circle which passes through the focus of the parabola y2=4xy^{2} = 4x and contained in it, isRadius of the largest circle which passes through the focus of the parabola y^ 2 = 4x and contained in it, is

Options

  1. A88
  2. B44
  3. C22
  4. D55

Correct answer

B. 44

Step-by-step solution

Let rr be the radius of the largest circle passing through the focus \left(1, 0\right) of y^{2} = 4x</p><p><imgsrc="/api/proxy−image?url=https</p><p><img src="/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fpyq%252Fbitsat%252F807de1a8-d722-452e-8c32-2df7ef662bcd-d48.png%3Falt%3Dmedia&clean=1&v=wm2" data-qx-orig-src="https://firebasestorage.googleapis.com/v0/b/quantrexacademy-app.firebasestorage.app/o/questions%2Ffigs%2Fpyq%2Fbitsat%2F807de1a8-d722-452e-8c32-2df7ef662bcd-d48.png?alt=media" data-qx-storage-src="https://firebasestorage.googleapis.com/v0/b/quantrexacademy-app.firebasestorage.app/o/questions%2Ffigs%2Fpyq%2Fbitsat%2F807de1a8-d722-452e-8c32-2df7ef662bcd-d48.png?alt=media" style="width: 325px; height: 250px;" /></p><p>Clearly, centre of the circle will be onX−axisanditscoordinatesare(1+r,0)-axis and its coordinates are \left(1 + r, 0\right).

The equation of the circle, is

\left(x - 1 - r\right)2 + y^{2} = r^{2}.</p><p>Ittouches.</p><p>It touchesy^{2} = 4x.Therefore,theequation(x−r−1)2+4x=r2. Therefore, the equation \left(x - r - 1\right)2 + 4x = r^{2} must have equal roots.

∴4(1−r)2−4(2r+1)=0∴ 4\left(1 - r\right)2 - 4\left(2r + 1\right) = 0

⇒r=4⇒ r = 4

Hence, option (b) is correct.

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