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BITSAT2022MathematicsComplex NumberActual

If |w|=2 , then the set of points z=w- 1 w is contained in or equal to the set of points z satisfying

Options

  1. AIm (z)=0
  2. B| Im (z)| 1
  3. C| Re (z)| 2
  4. D|z| 3

Correct answer

D. |z| 3

Step-by-step solution

We have, |w|=2 w=2( +i ) z=w- 1 w =2( +i )- 1 2 ( -i ) z= 3 2 + 5 2 i |z|= 9 4 + 25 4 = 17 2 < 3 Hence, option (d) is correct.

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