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AIIMS 201925 May

Exam: AIIMS
Year: 2019
Date: 25 May
Subject: Physics
Chapter: Rotational Motion

AIIMS 2019 · 25 May · Physics · Rotational Motion

A thin wire of mass M and length L is bent to form a circular ring....

A thin wire of mass

M

and length

L

is bent to form a circular ring. The moment of inertia of this ring about its axis is

Options

A $\frac{1}{4} M L^2$
B $\frac{1}{\pi^2} M L^2$
C $\frac{1}{4 \pi^2} M L^2$
D $\frac{1}{12} M L^2$

Correct answer

C. $\frac{1}{4 \pi^2} M L^2$

Step-by-step solution

A wire of length

L

is bent to form a circular ring of radius

R

,

\therefore \quad 2 \pi R=L

or

R=\frac{L}{2 \pi}

Moment of inertia of the circular ring about its axis is

I=M R^2=\frac{1}{4 \pi^2} M L^2

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