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AIIMS 201926 May
Exam
AIIMS
Year
2019
Date
26 May
Subject
Physics
Chapter
Rotational Motion

AIIMS 2019 · 26 May · Physics · Rotational Motion

The radius of gyration of a thin uniform circular disc (of radius R...

The radius of gyration of a thin uniform circular disc (of radius RR ) about an axis passing through its centre and lying in its plane isThe radius of gyration of a thin uniform circular disc (of radius R ) about an axis passing through its centre and

Options

  1. ARR
  2. BR/2R / \sqrt{2}
  3. CR/4R / 4
  4. DR/2R / 2

Correct answer

D. R/2R / 2

Step-by-step solution

Moment of inertia of the thin uniform circular disc of mass MM and radius RR about an axis passing through its centre and lying in its plane (i.e., about its diameter) is The radius of gyration of a thin uniform circular disc (of radius R ) about an axis passing through its centre and
From (i) and (ii), we get k2=R24k^2=\frac{R^2}{4} \quad or k=R2\quad k=\frac{R}{2}
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