The moment of inertia of a rod about an axis through its centre and perpendicular to it is (1)/(12) M L^2 (where M is the mass and L , the length of the rod). The rod is bent in the middle so that the two halves make an

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Correct answer: B. (1)/(12) M L^2

Moment of inertia of uniform rod about one end

=\frac{M L^2}{3}

.

\therefore

Moment of inertia of a rod about an axis passing through

O

and perpendicular to the plane of the rod will be =2

\left(\frac{M}{2}\right) \frac{(L / 2)^2}{3}=\frac{M L^2}{4 \times 3}=\frac{M L^2}{12}

The moment of inertia of a rod about an axis through its centre and perpendicular to it is (1)/(12) M L^2 (where M is

The moment of inertia of a rod about an axis through its centre and...

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