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NEET 2007
Exam
NEET
Year
2007
Subject
Physics
Chapter
Rotational Motion

NEET 2007 · Physics · Rotational Motion

A uniform rod AB of length I and mass m is free to rotate about...

A uniform rod AB\mathrm{AB} of length II and mass mm is free to rotate about point AA. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A\mathrm{A} is ml2/3m l^2 / 3, the initial angular acceleration of the rod will be A uniform rod AB of length I and mass m is free to rotate about point A . The rod is released from rest in the

Options

  1. Amgl2\frac{m g l}{2}
  2. B32gl\frac{3}{2} g l
  3. C3g2l\frac{3 g}{2 l}
  4. D2g3l\frac{2 g}{3 l}

Correct answer

C. 3g2l\frac{3 g}{2 l}

Step-by-step solution

Given that moment of inertia about AA is I=ml3/3I=m l^3 / 3 Now, torque about AA is given as τ=F×rτ=mg12Iα=mg12ml23α=mg12α=3g2l\begin{aligned} & \tau=F \times r \\ & \tau=m g \frac{1}{2} \\ & I \alpha=m g \frac{1}{2} \\ & \frac{m l^2}{3} \alpha=m g \frac{1}{2} \\ & \alpha=\frac{3 g}{2 l} \end{aligned})$
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