NEET2007PhysicsRotational MotionActual
A uniform rod AB of length I and mass m is free to rotate about point A . The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A is m l^2 / 3 , the initial angular acceleration of the rod will be
Options
- Am g l 2
- B3 2 g l
- C3 g 2 l
- D2 g 3 l
Correct answer
C. 3 g 2 l
Step-by-step solution
Given that moment of inertia about (A ) is (I=m l^3 / 3 ) Now, torque about (A ) is given as ( aligned & =F r & =m g 1 2 & I =m g 1 2 & m l^2 3 =m g 1 2 & = 3 g 2 l aligned )