BITSAT 2014
- Exam
- BITSAT
- Year
- 2014
- Subject
- Mathematics
- Chapter
- Probability
BITSAT 2014 · Mathematics · Probability
A coin is tossed 7 times. Each time a man calls head. Find the...
A coin is tossed 7 times. Each time a man calls head. Find the probability that he wins the toss on more occasions.
Options
- A
- B
- C
- D
Correct answer
B.
Step-by-step solution
The man has to win at least 4 times.
\begin{array}{r}
\therefore\text{ Reqd. probability }=\\
\qquad \begin{array}{r}7 \mathrm{C}_{4}\left(\frac{1}{2}\right)^{4} \cdot\left(\frac{1}{2}\right)^{3}+{ }^{7} \mathrm{C}_{5}\left(\frac{1}{2}\right)^{5} \cdot\left(\frac{1}{2}\right)^{2}\\
+{ }^{7} \mathrm{C}_{6}\left(\frac{1}{2}\right)^{6} \cdot \frac{1}{2}+{ }^{7} \mathrm{C}_{7}\left(\frac{1}{2}\right)^{7}\\
=\left({ }^{7} \mathrm{C}_{4}+{ }^{7} \mathrm{C}_{5}+{ }^{7} \mathrm{C}_{6}+{ }^{7} \mathrm{C}_{7}\right) \cdot \frac{1}{2^{7}}=\frac{64}{2^{7}}=\frac{1}{2}
\end{array}
\end{array}$