BITSAT 2020
- Exam
- BITSAT
- Year
- 2020
- Subject
- Mathematics
- Chapter
- Sequences and Series
BITSAT 2020 · Mathematics · Sequences and Series
A student read common difference of an A. P. as -2 instead of 2 and...
A student read common difference of an A. P. as -2 instead of 2 and got the sum of first 5 terms as -5. Actual sum of first five terms is
Step-by-step solution
25{2a+4(−2)}=−5⇒2a=6∴ Actual sum
=25{6+4(2)}=35
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