BITSAT 2020
- Exam
- BITSAT
- Year
- 2020
- Subject
- Mathematics
- Chapter
- Sequences and Series
BITSAT 2020 · Mathematics · Sequences and Series
If y=3 x+6 x^ 2 +10 x^ 3 + , ∞, then (1)/(3) y- 1.4 3^ 2 2 y^ 2 +...
If
y=3x+6x2+10x3+………,∞, then
31y−3221.4y2+3231.4.7y3−……∞ is equal to
Options
- Ax
- B1−x
- C1+x
- Dxx
Step-by-step solution
We have
y=3x+6x2+10x3+……⇒1+y=1+3x+6x2+10x3+…⇒1+y=(1−x)−3⇒1−x=(1+y)−1/3⇒x=1−(1+y)−1/3=31y−32⋅21.4y2+32⋅31⋅4⋅7y3−…
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