BITSAT2018MathematicsSequences and SeriesActual
If a , b , c are in GP and log a - log 2 b , log 2 b - log 3 c and log 3 c - log a are in AP , then a , b and c are the lengths of the sides of a triangle, which is
Options
- Aequilateral
- Bright angled
- Cacute-angled
- Dobtuse angled
Correct answer
D. obtuse angled
Step-by-step solution
Given, a ,   b ,   c are in GP . ∴   b 2 = a c and 2 log 2 b - log 3 c = log a - log 2 b + log 3 c - log a ⇒ b 2 = a c and 2 b = 3 c ∵   a + b = 5 a 3 > c ,   b + c = 10 a 9 > a and c + a = 13 a 9 > b ∴   a ,   b ,   c are the sides of a triangle. Also, a is the greatest side ∴   cos A = b 2 + c 2 - a 2 2 b c = - 29 48 < 0 ∴   ∆ ABC is an obtuse angled triangle. Hence, option (d) is correct.