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BITSAT 2010
Exam
BITSAT
Year
2010
Subject
Physics
Chapter
Alternating Current

BITSAT 2010 · Physics · Alternating Current

An alternating voltage V=V_ 0 sin ot is appliedacross a circuit. As...

An alternating voltage V=V0V=V_{0} sin ot is appliedacross a circuit. As a result, a current I=I0sin⁡(ωt−π/2)I=I_{0} \sin (\omega t-\pi / 2) flows in it. The power consumed per cycle is

Options

  1. Azero
  2. B0.5V00.5 \mathrm{ V}_{0}\mathrm{I}0_{0}
  3. C0.707V00.707 \mathrm{ V}_{0}\mathrm{I}0_{0}
  4. D1.414V01.414 \mathrm{ V}_{0}\mathrm{I}0_{0}

Correct answer

A. zero

Step-by-step solution

The phase angle between voltage V\mathrm{V} and current I is π/2\pi / 2.
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