A resistance R and inductance L and a capacitor C all are connected in series with an AC supply. The resistance of R is 16 ohm and for a given frequency, the inductive reactance of L is 24 ohm and capacitive reactance

Correct answer: D. 80,120,60 volt V_ R =i R=5 × 16=80 Volt array l V_ L =i ×(ω L)=5 ×24=120 Volt V_ C =i ×(l/ ω C)=5 ×12=60 Volt array

BITSAT 2010

BITSAT 2010 · Physics · Alternating Current

A resistance R and inductance L and a capacitor C all are connected...

A resistance

\mathrm{R}

and inductance

\mathrm{L}

and a capacitor

\mathrm{C}

all are connected in series with an AC supply. The resistance of

\mathrm{R}

is 16 ohm and for a given frequency, the inductive reactance of

L

is 24 ohm and capacitive reactance of

\mathrm{C}

12 \mathrm{ohm}.

If the current in the circuit is 5 amp., find the potential difference across

\mathrm{R}, \mathrm{L}

and

\mathrm{C}

D. 80,120,60 volt

\mathrm{V}_{\mathrm{R}}=\mathrm{i} \mathrm{R}=5 \times 16=80 \mathrm{Volt}

\begin{array}{l}\mathrm{V}_{\mathrm{L}}=\mathrm{i} \times(\omega \mathrm{L})=5 \times24=120 \mathrm{Volt}\\ \mathrm{V}_{\mathrm{C}}=\mathrm{i} \times(\mathrm{l}/ \omega \mathrm{C})=5 \times12=60 \mathrm{Volt} \end{array}