A wire of a certain material is stretched slowly by ten per cent....

($\mathrm{R}=\frac{\rho \mathrm{l}}{\mathrm{A}}$) Now, (1=1+$\frac{1}{10}=\frac{111}{10}$) and therefore, ($\mathrm{A}=\frac{10 \mathrm{~A}}{11}$) So (\mathrm{R}^{\prime}=$\frac{\mathrm{p} \times\left(\frac{111}{10}\right)}{\frac{10 \mathrm{~A}}{11}}=\frac{\rho \mathrm{l}}{\mathrm{A}} \times \frac{(11)^{2}}{(10)^{2}}=$1.21 $\mathrm{R}$) Now resistance becomes $1.21$ times of initial and specific resistance is the intrinsic property so remains same.