BITSAT2019PhysicsCurrent ElectricityActual
The value of current I as shown in the given circuit diagram is
Options
- A2   A
- B1 . 5   A
- C0 . 9   A
- D0 . 2   A
Correct answer
C. 0 . 9   A
Step-by-step solution
The given circuit can be redrawn as Since, R A B R B C = R A D R D C = 1 2 , hence, it is a balanced Wheatstone bridge, therefore current flowing in arm B D = 0 ∴         R eq = 10 + 20 ∥ 6 + 12 = 30 ∥ 18 = 30 × 18 30 + 18 = 11 . 25   Ω ∴       I = V R eq = 10 11 . 25 = 0 . 89   A = 0 . 9   A