A carbon resistor of (56 ± 5. 6)kΩ is to be marked with rings of...

Given, $R = \left(56 \pm 5. 6\right)kΩ$

$= 56kΩ \pm 10$ of $56kΩ$
$= 56 \times {10}^{3} \pm 10$

As per the colour code for carbon resistors, the colour assigned to numbers

$5 \to$ Green
$6 \to$ Blue
$3 \to$ Orange

For $10$ accuracy or tolerance, the colour is silver. Hence, the bands of colours of carbon resistor in sequence are green, blue, orange and silver.