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BITSAT 2016
Exam
BITSAT
Year
2016
Subject
Physics
Chapter
Current Electricity

BITSAT 2016 · Physics · Current Electricity

The drift velocity of electrons in silver wire with cross-sectional...

The drift velocity of electrons in silver wire with cross-sectional area 3.14×10−6m23.14 \times 10^{-6} \mathrm{ m}^{2} carrying a current of 20A20 \mathrm{ A} is. Given atomic weight of Ag=108,\mathrm{Ag}=108, density of silver =10.5×103kg/\mathrmm3=10.5 \times 10^{3} \mathrm{ kg} / \mathrmm^{3}

Options

  1. A2.798×10−4m/sec⁡2.798 \times 10^{-4} \mathrm{ m} / \mathrm\sec
  2. B67.98×10−4m/sec⁡67.98 \times 10^{-4} \mathrm{ m} / \mathrm\sec
  3. C0.67×10−4m/sec⁡0.67 \times 10^{-4} \mathrm{ m} / \mathrm\sec
  4. D6.798×10−4m/sec⁡6.798 \times 10^{-4} \mathrm{ m} / \mathrm\sec

Correct answer

D. 6.798×10−4m/sec⁡6.798 \times 10^{-4} \mathrm{ m} / \mathrm\sec

Step-by-step solution

\quad Number of electrons per kg of silver =6.023×1026108\frac{6.023 \times 10^{26}}{108} Number of electrons per unit volume of silver \begin{array}{c} n=\frac{6.023 \times 10^{26}}{108} \times10.5 \times10^{3} \\ \qquad \begin{array}{c} v_{d}=\frac{I}{n e A}\\ =\frac{20}{6.023 \times 10^{26} \times 10.5 \times 10^{3} \times 1.6 \times 10^{-19} \times 3.14 \times 10^{-6}} \times108 \\ =6.798 \times10^{-4} \mathrm{ m}/ \mathrm\sec. \end{array} \end{array}$
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