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BITSAT 2012
Exam
BITSAT
Year
2012
Subject
Physics
Chapter
Current Electricity

BITSAT 2012 · Physics · Current Electricity

Three voltmeters A, B and C having resistances R, 1.5 R and 3 R,...

Three voltmeters A,B\mathrm{A}, \mathrm{B} and C\mathrm{C} having resistances R,1.5R\mathrm{R}, 1.5 \mathrm{R} and 3R,3 \mathrm{R}, respectively, are connected as shown. When some potential difference is applied between X\mathrm{X} and Y,\mathrm{Y}, the voltmeter readings are VA,VB\mathrm{V}_{\mathrm{A}}, \mathrm{V}_{\mathrm{B}} and VC\mathrm{V}_{\mathrm{C}} respectively. Then - Three voltmeters A, B and C having resistances R, 1.5 R and 3 R, respectively, are connected as shown. When some

Options

  1. AVA≠VB=VCV_{A} \neq V_{B}=V_{C}
  2. BVA=VB≠VCV_{\mathrm{A}}=V_{\mathrm{B}} \neq V_{\mathrm{C}}
  3. CVA≠VB≠VC\mathrm{V}_{\mathrm{A}} \neq \mathrm{V}_{\mathrm{B}} \neq \mathrm{V}_{\mathrm{C}}
  4. DVA=VB=VCV_{A}=V_{B}=V_{C}

Correct answer

D. VA=VB=VCV_{A}=V_{B}=V_{C}

Step-by-step solution

VA=IRVB=(2I3)1.5R=IRVC=(13)3R=IR∴VA=VB=VCV_{A}=I RV_{B}=\left(\frac{2 I}{3}\right)^{1}.5 R=I R \quad V_{C}=\left(\frac{1}{3}\right)^{3} R=I R\therefore \quad V_{A}=V_{B}=V_{C}
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