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BITSAT 2010
Exam
BITSAT
Year
2010
Subject
Physics
Chapter
Current Electricity

BITSAT 2010 · Physics · Current Electricity

The power dissipated in the circuit shown in the figure is 30...

The power dissipated in the circuit shown in the figure is 30 Watts. The value of RR is The power dissipated in the circuit shown in the figure is 30 Watts. The value of R is

Options

  1. A20Ω20 \Omega
  2. B15Ω15 \Omega
  3. C10Ω10 \Omega
  4. D30Ω30 \Omega

Correct answer

C. 10Ω10 \Omega

Step-by-step solution

P=V2Req1Req=1R+15=5+R5RReq=(5R5+R)P=30WP=\frac{V^{2}}{R_{\mathrm{eq}}}\frac{1}{R_{\mathrm{eq}}}=\frac{1}{R}+\frac{1}{5}=\frac{5+R}{5 R} R_{\mathrm{eq}}=\left(\frac{5 R}{5+R}\right) P=30 \mathrm{ W} Substituting the values in equation (i) 30=(10)2(5R5+R)⇒\frac{(10)^{2}}{\left(\frac{5 R}{5+R}\right)} \Rightarrow R=10 \Omega
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