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BITSAT2019PhysicsMotion in Two DimensionsActual

A projectile is given an initial velocity of i ^ + 3 j ^ m s - 1 , where i ^ is along the ground and j ^ is along the vertical. Then, the equation of the path of projectile is [ Take, g = 10 m s - 2

Options

  1. Ay = 3 x - 5 x 2
  2. By = 3 x + 5 x 2
  3. Cx = 3 y + 5 x 2
  4. Dx 2 = y 2 + 3

Correct answer

A. y = 3 x - 5 x 2

Step-by-step solution

Velocity of projectile at time t is given by v = u - g   t   j ^ v = i ^ + 3   j ^ - 10   t   j ^ ∴    r = ∫ v   d t = ∫   i ^ + 3   j ^ - 10   t   j ^   d t = t   i ^ + 3   t   j ^ - 10 t 2 2 j ^ = t   i ^ + 3   t   j ^ - 5   t 2   j ^ r = t   i ^ + 3   t - 5   t 2   j ^ or x   i ^ + y   j ^ = t   i ^ + 3   t - 5   t 2   j ^ On comparing, x = t

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