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BITSAT 2017
Exam
BITSAT
Year
2017
Subject
Physics
Chapter
Motion in Two Dimensions

BITSAT 2017 · Physics · Motion in Two Dimensions

At what angle θ to the horizontal should an object is projected so...

At what angle θ\theta to the horizontal should an object is projected so that the maximum height reached is equal to the horizontal range?

Options

  1. A\tan^{-1} (2)</span>\left(2\right)</span>
  2. Btan⁡−1(4)\tan^{-1} \left(4\right)
  3. Ctan⁡−1(23)\tan^{-1} ( \dfrac{2}{3} )
  4. Dtan⁡−1(3)\tan^{-1} \left(3\right)

Correct answer

B. tan⁡−1(4)\tan^{-1} \left(4\right)

Step-by-step solution

Given, H=RH = R

or u2sin⁡2θ2g=u2sin⁡2θg\dfrac{u^{2}\sin^{2}\theta}{2g} = \dfrac{u^{2}\sin 2\theta}{g}

sin⁡(θ)\timessin(θ)2=2sin⁡(θ)\timescos(θ)\dfrac{\sin \left(\theta\right) \timessin \left(\theta\right)}{2} = 2\sin \left(\theta\right) \timescos \left(\theta\right)

⇒tanθ=4⇒ tan\theta =4

⇒θ=tan⁡−1(4)⇒ \theta = \tan^{-1} \left(4\right)

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