BITSAT2017PhysicsMotion in Two DimensionsActual
The horizontal range and maximum height attained by a projectile are R and H respectively. If a constant horizontal acceleration a = g 4 is imparted to the projectile due to wind, then its horizontal range and maximum height will be
Options
- AR + H , H 2
- BR + H 2 , 2 H
- CR + 2 H , H
- DR + H , H
Correct answer
D. R + H , H
Step-by-step solution
T = 2 U y g H = U y 2 2 g Here maximum height will be same as H because there is no acceleration change in vertical direction. and R = U x × T When a horizontal acceleration is also given to the projectile U y , T and H will remain unchanged while range will become R ' = U x × T + 1 2 a T 2 = R + 1 2 g 4 4 U y 2 g 2 = R + H    ∵ a = g 4 Therefore horizontal range & maximum height will be R + H   &   H .