A wheel of radius R rolls on the ground with a uniform velocity v ....

A wheel of radius

\mathrm{R}

rolls on the ground with a uniform velocity

\mathrm{v}

. The relative acceleration of topmost point of the wheel with respect to the bottom most point is A wheel of radius R rolls on the ground with a uniform velocity v . The relative acceleration of topmost point of the

A wheel of radius R rolls on the ground with a uniform velocity v . The relative acceleration of topmost point of the

Options

A $\frac{\mathrmv^{2}}{\mathrm{R}}$
B $\frac{2 \mathrmv^{2}}{\mathrm{R}}$
C $\frac{\mathrmv^{2}}{2 \mathrm{R}}$
D $\frac{4 \mathrmv^{2}}{\mathrm{R}}$

Correct answer

B. $\frac{2 \mathrmv^{2}}{\mathrm{R}}$

Step-by-step solution

a_{\mathrm{CM}}=0 \quad\left[\mathrm{v}_{\mathrm{CM}}=\right.

constant

]

, Tangential acceleration of each point \left|\overrightarrow{\mathrm{a}}_{\mathrm{AB}}\right|=\frac{2 \mathrmv^{2}}{\mathrm{R}}

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