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BITSAT 2012
Exam
BITSAT
Year
2012
Subject
Physics
Chapter
Motion in Two Dimensions

BITSAT 2012 · Physics · Motion in Two Dimensions

The range of the particle when launched at an angle of 15^ ^ with...

The range of the particle when launched at an angle of 15∘15^{{}^{\circ}} with the horizontal is 1.5km1.5 \mathrm{ km}. What is the range of the projectile when launched at an angle of 45∘45^{{}^{\circ}} to the horizontal.

Options

  1. A1.5km1.5 \mathrm{ km}
  2. B3.0km3.0 \mathrm{ km}
  3. C6.0km6.0 \mathrm{ km}
  4. D0.75km0.75 \mathrm{ km}

Correct answer

B. 3.0km3.0 \mathrm{ km}

Step-by-step solution

1.5=\mathrmu2sin⁡30g;R=\mathrmu2sin⁡90g=3km1.5=\frac{\mathrmu^{2} \sin 30}{\mathrm{ g}} ; \mathrm{R}=\frac{\mathrmu^{2} \sin 90}{\mathrm{ g}}=3 \mathrm{ km}
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