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BITSAT2011PhysicsOscillationsActual

A mass m is suspended from a spring of force constant k and just touches another identical spring fixed to the floor as shown in the figure. The time period of small oscillations is

Options

  1. A2 m k
  2. Bm k + m k / 2
  3. Cm 3 k / 2
  4. Dm k + m 2 k .

Correct answer

D. m k + m 2 k .

Step-by-step solution

When the spring undergoes displacement in the downward direction it completes one half oscillation while it completes another halfoscillation in the upward direction. The total time period is: T = m k + m 2 k

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