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BITSAT 2010

Exam: BITSAT
Year: 2010
Subject: Physics
Chapter: Oscillations

BITSAT 2010 · Physics · Oscillations

A simple pendulum has time period 't'. Its time period in a lift...

A simple pendulum has time period 't'. Its time period in a lift which is moving upwards with acceleration

3 \mathrm{ ms}^{-2}

is

Options

A $t \sqrt{\frac{9.8}{12.8}}$
B $t \sqrt{\frac{12.8}{9.8}}$
C $\mathrm{t} \sqrt{\frac{9.8}{6.8}}$
D $\mathrm{t} \sqrt{\frac{6.8}{9.8}}$

Correct answer

A. $t \sqrt{\frac{9.8}{12.8}}$

Step-by-step solution

\mathrm{t} \propto \frac{1}{\sqrt{9.8}}, \mathrmt^{\prime} \propto \frac{1}{\sqrt{12.8}}\left(\because \mathrmg^{\prime}=9.8+3=12.8\right)\therefore \frac{\mathrmt^{\prime}}{\mathrm{t}}=\sqrt{\frac{9.8}{12.8}} \Rightarrow \mathrmt^{\prime}=\sqrt{\frac{9.8}{12.8}} \mathrm{t}

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