Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their products given in List-II and choose the correct option. List-I List-II (P) P _ 2 O _ 3 + 3 H _ 2 O → (1) P ( O ) ( OCH _ 3 )

Question

Quantrex Academy · Accepted Answer

Correct answer: D. P → 2; Q → 3; R → 4; S → 5

Phosphorus trioxide reacts with water to form phosphorous acid,
${P}_{2}{O}_{3} + 3{H}_{2}O \to 2{H}_{3}{PO}_{3}$
When acetic acid is heated with phosphorus pentachloride, acetyl chloride is obtained. In this reaction, $- COOH$ group is converted to $- COCl$ group. The side products are phosphorus oxychloride and $HCl$ .
${PCl}_{5} + {CH}_{3}COOH \to {CH}_{3}COCl + {POCl}_{3} + HCl$
${P}_{4}$ undergo disproportionation reaction with sodium hydroxide.
${P}_{4} + 3NaOH + 3{H}_{2}O\to{PH}_{3} + 3{NaH}_{2}{PO}_{2}$
Due to the presence two $P - H$ bonds, ${H}_{3}{PO}_{2}$ acts as reducing agent. It reduces ${Ag}^{+}$ to $Ag$ .
${H}_{3}{PO}_{2} + {H}_{2}O + {AgNO}_{3} \to {H}_{3}{PO}_{4} + {HNO}_{3} + Ag ↓$

	List-I		List-II
(P)	${P}_{2}{O}_{3} + 3{H}_{2}O \to$	(1)	$P ( O ) \left({OCH}_{3}\right){Cl}_{2}$
(Q)	${P}_{4} + 3NaOH + 3{H}_{2}O \to$	(2)	${H}_{3}{PO}_{3}$
(R)	${PCl}_{5} + {CH}_{3}COOH \to$	(3)	${PH}_{3}$
(S)	${H}_{3}{PO}_{2} + 2{H}_{2}O + 4{AgNO}_{3} \to$	(4)	${POCl}_{3}$
		(5)	${H}_{3}{PO}_{4}$

Match the reactions (in the given stoichiometry of the reactants)...

Options

Correct answer

Step-by-step solution

More from Carboxylic Acid Derivatives