Consider the following species: SOCl_2 , XeOF_4 , ClF_3 , ClF_5 ,...

Let us determine the hybridization and shape of each given species by finding the number of bond pairs (bp) and lone pairs (lp) on the central atom:

$\text{SOCl}_2$: Central atom S has 6 valence electrons. It forms 3 $\sigma$ bonds (one with O, two with Cl) and has 1 lone pair. Steric number = 4 ($sp^3$). Shape is Trigonal Pyramidal.

$\text{XeOF}_4$: Central atom Xe has 8 valence electrons. It forms 5 $\sigma$ bonds (one with O, four with F) and has 1 lone pair. Steric number = 6 ($sp^3d^2$). Shape is Square Pyramidal.

$\text{ClF}_3$: Central atom Cl has 7 valence electrons. It forms 3 $\sigma$ bonds with F and has 2 lone pairs. Steric number = 5 ($sp^3d$). Shape is T-shaped.

$\text{ClF}_5$: Central atom Cl has 7 valence electrons. It forms 5 $\sigma$ bonds with F and has 1 lone pair. Steric number = 6 ($sp^3d^2$). Shape is Square Pyramidal.

$\text{XeF}_5^+$: Central atom Xe has 8 valence electrons. The positive charge leaves 7 valence electrons. It forms 5 $\sigma$ bonds with F and has 1 lone pair. Steric number = 6 ($sp^3d^2$). Shape is Square Pyramidal.

$\text{SO}_3^{2-}$: Central atom S has 6 valence electrons. The $-2$ charge gives 8 valence electrons. It forms 3 $\sigma$ bonds with O and has 1 lone pair. Steric number = 4 ($sp^3$). Shape is Trigonal Pyramidal.

$\text{XeF}_3^+$: Central atom Xe has 8 valence electrons. The positive charge leaves 7 valence electrons. It forms 3 $\sigma$ bonds with F and has 2 lone pairs. Steric number = 5 ($sp^3d$). Shape is T-shaped.

$\text{SF}_4$: Central atom S has 6 valence electrons. It forms 4 $\sigma$ bonds with F and has 1 lone pair. Steric number = 5 ($sp^3d$). Shape is See-saw.

Counting the species for each shape:
(P) See-saw: $1$ ($\text{SF}_4$)
(Q) T-Shaped: $2$ ($\text{ClF}_3$, $\text{XeF}_3^+$)
(R) Trigonal Planar: $0$ (None)
(S) Square Pyramidal: $3$ ($\text{XeOF}_4$, $\text{ClF}_5$, $\text{XeF}_5^+$)

Matching with List-II:
P $\rightarrow$ 1
Q $\rightarrow$ 2
R $\rightarrow$ 5
S $\rightarrow$ 3

Answer: P $\rightarrow$ 1; Q $\rightarrow$ 2; R $\rightarrow$ 5; S $\rightarrow$ 3